WebDec 23, 2024 · We know the area of trapezium= 1/2× ( sum of parallel sides)× height so, 24.5= 1/2× (10+4)×h h= 49/14 cm= 3.5cm now, the area of circular part (ie. AEB)= 1/4 × 22/7 × 3.5×3.5 = 8.625cm^2 so, area of shaded region= 24.5 - 8.625=15.875 sq cm wrong sum Advertisement Lokeshaswale8281 The answer is added to the attachment below …WebJan 26, 2024 · In the given figure ABCD is a trapezium of area 24.5 CM ^2. If AB।। BC <dab = 90' , ad="10cm," bc="4" cm and abe is a quadrant of circle. then find the - 7835480
4. In figure, ABCD is a trapezium of area 24.5 sq. cm. in it, A... Filo
WebABCD is trapezium of area 24.5 sq.cm.in it AD BC angle DAB=90 degree AD=10cm and BC =4cm. If ABE is a quadrant of a circlefind the area of the shaded region. AboutPressCopyrightContact... WebIn the Following Figure, Abcd is a Trapezium of Area 24.5 Cm2 , If Ad Bc, ∠Dab = 90°, Ad = 10 Cm, Bc = 4 Cm and Abe is Quadrant of a Circle, Then Find the Area of the Shaded Region. [Cbse 2014] gave false hope to crossword clue
Q21 In the given figure, ABCD is a trapezium of area 24.5 cm2. If …
WebApr 30, 2024 · It is given that the area of trapezium ABCD is 24.5 cm^2 . And AD BC WebMar 3, 2014 · Area of the trapezium = h/2 (a + b) where a and b are the parallel sides and h is the perpendicualr distance between the parallel sides. Area of the trapezium ABCD = AB/2 … WebABCDis a trapezium of area 24.5sq. cm. In it, AD∥BC,∠DAB=90∘,AD=10 cm and BC=4 cm. If ABEis a quadrant of a circle, find the area of the shaded region. [Take π=722 ]. Hard Open in App Solution Verified by Toppr Given: AD=10cm BC=4cm Area of trapezium =24.5 cm2 Area of trapezium =2a+b ×height 24.5=2AD+BC ×AB 24.5=210+4 ×AB AB=3.5cm Radius =3.5cmgave for a bit crossword clue